A hollow shaft has a cross-sectional area 125.6cm2 and a bore of 8cm in diameter. Calculate the outer diameter of the shaft to 2s. f. With the explanations please

The outer diameter of the shaft to 2s.f is  12.65cm

Step-by-step explanation:

We know that the expression for the area of a circular cross section is

A=

given data

area of cross section=

bore diameter d= 8cm

from the area of cross section we can solve for the outer diameter D

solving for D we have

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

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