A container has 14 yellow chips, 10 blue chips, and 12 red chips in it. One chip is randomly chosen from the container, then a second chip is randomly chosen after replacing the first chip. What is the probability that both chips are red? IN SIMPLEST FORM

1/9

Step-by-step explanation:

So, we are given the following data or parameters or infomation in the question above;

=>" A container has 14 yellow chips, 10 blue chips, and 12 red chips in it. "

=> "One chip is randomly chosen from the container, then a second chip is randomly chosen after replacing the first chip."

Therefore, the total number of chips in the container = 14 + 10 + 12 = 36 chips.

The probability of drawing a red chip in the first draw = 12/36 = 1/3.

The probability of drawing a red chip in the second draw = 1/3 also.

Thus, the probability that both chips are red => 1/3 × 1/3 = 1/9.

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29

multiply then divide

step-by-step explanation: