If f(x)=7x-3and g(x)=x^2-4x-8 find (f+g)(x)

The value of (f+g)(x) is x^2 + 3x - 11

You can combine this by simply adding the like terms. Start by adding together all of the x^2 terms. Since only g(x) has one of those, we use that in its entirety.

x^2

Next we add together the x terms. f(x) has 7x and g(x) has -4x.

7x + -4x = 3x

Finally, we add together the constants. f(x) has -3 and g(x) has -8.

-3 + -8 = -11

With all of the like terms combined, we simply take the answers and put them together.

x^2 + 3x - 11

Step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

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step-by-step explanation: