A bag contains 7 green balls and 3 white balls. A ball is drawn from the bag and replaced,

before a second draw is made. What is the

probability that: (a) they are both white (b) one

is white one is green

10 total balls.

A) first pick white = 3/10

Second pick white = 3/10

Both white = 3/10 x 3/10 = 9/100

B) 3/10 x 7/10 = 21/100

answer: i would say b

step-by-step explanation:

with the way the question is worded, i believe b is the answer

the cost of the apple depends on the weight

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0