Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2, 0) left parenthesis, right parenthesis, B(6, 0) right parenthesis, C(6, 7) right parenthesis, and D(2, 7). What is the area of rectangle ABCD?

28 units squared

Step-by-step explanation:

It becomes a lot easier if you just try to plot the points on an axis, but i'll try to explain.

A and B are x-intercepts and the bottom two corners of the rectangle. C and D are the top two corners of the rectangle. Like any other case, to find the area, you need just two things:

1) height

2) width

To find the width:

Consider the distance between A and B - the bottom 2 corners. The coordinates are (2,0) and (6,0). Since we are trying to work out the width, just worry about the x-values. So, 6-2 = 4 and that is the width.

To find the height:

We'll take coordinates B and C - the bottom and top right corners of the rectangle. Coordinates are (6,0) and (6,7). Since we are trying to work out the height, just look at the y-values. So, 7 (top corner) - 0 (bottom corner) = 7, which is the height.

To figure out area:

Just multiply width by height, so:

4 x 7 = 28

And the area is 28 units squared. Change the units into whatever unit of measurement they give you (m, cm, mm etc.)

Hope this helped :)

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

i'm not really sure how to answer that

step-by-step explanation: