If you’re good with permutations in math 30 please help and answer this easy question below real answers only a graduating class has 10 students with 6 boys and 4 girls. the number of ways the students can be arranged in a line if the girls must be together and the boys must be together is

a) 2(6!)(4!)

b) 10!

c) 6!4!

d) 2 (6) (4!)

 a) 2(6!)(4!)

Step-by-step explanation:

The number of ways the boys can be arranged is: 6!

The number of ways the girls can be arranged is: 4!

The number of ways the groups (boys & girls) can be arranged is: 2

Girls could be in the front .. or in the back ... of the line.

Put these together to get: 6! × 4! × 2

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation:

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)