Last years freshman class at big state university totaled $5330 students. Of those, $1258 received a merit scholarship to help offset tuition cost their freshman year. The amount a student received was N($3464, 489). If the cost of full tuition was $4450 last year, what percentage of students who received a merit scholarship did not receive enough to cover full tuition?

2.17% of students who received a merit scholarship did not receive enough to cover full tuition

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

If the cost of full tuition was $4450 last year, what percentage of students who received a merit scholarship did not receive enough to cover full tuition?

This is 1 subtracted by the pvalue of Z when X = 4450. So

has a pvalue of 0.9783.

1 - 0.9783 = 0.0217

2.17% of students who received a merit scholarship did not receive enough to cover full tuition

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

76%

step-by-step explanation:

24% are dogs and the remaining is 76% because 100-24=76