How many ways can you distribute $4$ identical balls among $4$ different boxes?

 a reasonable answer would be 4 balls maximum and 0 balls minimum to any of 4 given boxes with the 4 box totals = 4 balls.

Step-by-step explanation:

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

twenty-six miles over two gallons because the proportion for the original 13 miles to one gallon would be written 13/1 and, doing the same thing to the top and bottom, i multiplied by 2 and got 26/2