Draw the line that is parallel to y = 2x + 5 and passes through the point (2,3). Select the point through which the
graph passes.
C
D
A
E

point C (-1, -3)

Step-by-step explanation:

The line you are looking for already has two givens: m = 2 and it has coordinate (2,3) on it. You can plug these in to find the equation of the line and then see which of the 4 points it must pass through.

         3 = 2(2) + b

         -1 = b

         the line you are looking for is y = 2x - 1

First, you can rule out points D and B, because after a quick look, you can see that a line with a slope of 2 wouldn't come close to the point (2,3). Now you can choose between C (-1, -3) and A (-2, -3).

         Now you can plug in the points C and A into the equation of the line that was obtained in the first part of this answer.

         checking point A: -3 = 2(-2) - 1

                                        -3= -5

                                       not true, so now we check point C

         checking point C: -3 = 2(-1) - 1

                                       -3 = -2 - 1

                                       -3 = -3

                                       true, so the point must be C

I hope you did good

Step-by-step explanation:

I see that it's from an hour ago, I hope you did well <3

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.