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Mathematics, 12.06.2020 14:57 kayla4352

Will give brainliest to whoever solves this for me! Complete the proof of the Law of Sines/Cosines.
Given triangle ABC with altitude segment AD labeled x. Angles ADB and CDA are _1._ by the definition of altitudes, making triangle ABD and triangle CDA right triangles. Using the trigonometric ratios sine of B equals x over c and sine of C equals x over b. Multiplying to isolate x in both equations gives x = _2._ and x = b â‹… sinC. We also know that x = x by the reflexive property. By the substitution property, _3._. Dividing each side of the equation by bc gives: sine of B over b equals sine of C over c.
1. altitudes
2. b â‹… sinB
3. b â‹… sinB = c â‹… sinC

1. right angles
2. b â‹… sinB
3. b â‹… sinB =c â‹… sinB

1. altitudes
2. c â‹… sinB
3. c â‹… sinB = b â‹… sinC

1. right angles
2. c â‹… sinB
3. c â‹… sinB = b â‹… sinC


Will give brainliest to whoever solves this for me!

Complete the proof of the Law of Sines/Cosine

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Will give brainliest to whoever solves this for me! Complete the proof of the Law of Sines/Cosines....
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