Analyze the graphed function to find the local minimum and the local maximum for the given function. On a coordinate plane, a curved line with minimum values of (0.6, negative 8) and (3.4, negative 8), and a maximum value of (2, 0), crosses the x-axis at (0, 0), (2, 0), and (4, 0), and crosses the y-axis at (0, 0). Which statements about the local maximums and minimums for the given function are true? Choose three options. Over the interval [1, 3], the local minimum is 0 Over the interval [2, 4], the local minimum is –8. Over the interval [3, 5], the local minimum is –8. Over the interval [1, 4], the local maximum is 0. Over the interval [3, 5], the local maximum is 0

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

- both graphs increase on their domain.

- the graphs of both functions have the same x-intercept.

- neither graph has a y-intercept.