In a standard 52−card deck, half of the cards are red and half are black. The 52 cards are divided evenly into 4 suits: spades, hearts, diamonds, and clubs. Each suit has three face cards (jack, queen, king), and an ace. Each suit also has 9 cards numbered from 2 to 10. Suppose a solitaire player has played 800 games. Predict how many times the player turned over a black card as the first card.

The player can expect to turn over a black card about

( answer ) times.

the player can expect to turn over a black card about 400 times.

Step-by-step explanation:

the way to solve a probability question is like this:

there are 52 total cards, out of those 52 cards, half of them are black cards.

that means 1/2 of 52 = black cards

if the plays 800 times, and half of the cards are black, the player can expect to have a 50% chance of flipping over a black card.

800/50 = 400.

therefore the player can expect to have flipped a black card 400 times.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

no he doesnt because "-16' is negatiive

step-by-step explanation: