The mileages of cars in a fleet of cars are normally distributed with a mean mileage of 52,000 miles and a standard deviation of 2,000 miles. What is the probability of randomly selecting a car with a mileage less than 52,000 miles?

50%

Step-by-step explanation:

We have that the mean is 52000 miles (m) and the standard deviation is 2000 miles (sd), so we are asked:

P (x <52000)

P ((x - m) / sd <(52000 -52000) /2)

P (z <0)

If we look in the normal distribution table we have to:

P (x <52000) = 0.5

That is, the probability is of randomly selecting a car with a mileage less than 52,000 miles 50%

the answer is:

the correct option is the option b.

to calculate the surface area of the right cylinder, we need to use the following formula:

from the picture we know that:

so, substituting and calculting we have:

hence, we have that the correct option is the option b.

have a nice day!

the circumference is c≈245.04