What are the coordinates for the center of the circle and the length of the radius of the circle whose equation is x2+y2=8x-6y+39? A. center (-4,3) and radius 64
B. center (4,-3) and radius 64
c. center (-4,3) and radius 8
D. center (4,-3) and radius 8

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.

-1   1/6.   you dont subtract the denominators

step-by-step explanation: