In △ ABC, ∠C = 57° and ∠A = 103°. Side CB= 6.5 cm. Draw △ A′B′C′ under the same condition as △ ABC. Leave all construction marks as evidence of your work, and label all side and angle measurements(use text box). What can you conclude about △ ABC and △ A′B′C′? Justify your response.

  ΔA'B'C' is congruent to ΔABC

Step-by-step explanation:

See attached for the construction of ΔA'B'C'. (The vertices are labeled ABC.)

We computed angle B to be ...

  ∠B = 180° -∠A -∠C

  ∠B = 180° -103° -57° = 20°

We constructed segment BC of length 6.5. Then we constructed angles of 20° and 57° from B and C, respectively. The location where the rays from those angles cross is point A', and the angle there is 103°, as required.

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ΔA'B'C' is congruent to ΔABC by the ASA congruence postulate.

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

really really sorry if i'm

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