Please help me with the question

x²+6y=9

Step-by-step explanation:

r=3/(1+sin θ)

r(1+sin θ)=3

r+rsin θ=3

√(x²+y²)+y=3

√(x²+y²)=3-y

squaring both sides

x²+y²=9+y²-6y

x²=-6y+9

or x²+6y=9

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length