What is the equation of a line, in standard form, for the line with slope 5 and a y-intercept of -4? a) 5x + y - 4 = 0
b) 5x - y + 4 = 0
c) 5x - y - 4 = 0
d) 5x + y + 4 = 0

Option c

Step-by-step explanation:

Converting all options into slope intercept, you get

a) y=-5x+4

b) y=5x+4

c) y=5x-4

d) y=-5x-4

option c has slope 5 and y-intercept -4

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²