For the graph of the rational function f(x)=x^2-15+56 over
x+7, identity all discontinuities as either a removable discontinuity or a vertical asymptote

A. removable discontinuity at x=-7

B. Vertical asymptote is x=7

C. vertical asymptote is at x=-7

D. Removable discontinuity at x=7

answer:

(-8,7)

explanation:

we know that  

f

(

−

3

)

=

7

therefore, if we wish to get the output as 7, in the function, we need to have our input to be -3.

looking at the function  

f

(

x

+

5

)

, what should the value of x be, such that the input in the function becomes 7?

we simply equate the terms,

x

+

5

=

−

3

x

=

−

8

thus, the point on the new function would be  

(

−

8

,

7

)

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

~just a girl in love with shawn mendes