Using the definition of the derivative, find f prime (x ). Then find f prime (1 ), f prime (2 ), and f prime (3 )when the derivative exists.

Step-by-step explanation:

We need the function f(x) to be able to determine the required.

Suppose we were given a function

f(x) = y

f'(x) represents the first derivative of the function f(x) = y.

f'(1) represents the value of the first derivative of the function f(x) = y after replacing x by 1.

f'(5) represents the value of the first derivative of the function f(x) = y after replacing x by 5.

Example: Suppose f(x) = x² + 3x, find

f'(x), f'(1), and f'(5).

f'(x) = 2x + 3

f'(1) = 2(1) + 3 = 5

f'(5) = 2(5) + 3 = 13

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!