What is the standard equation of the circle in the graph

option 1

Step-by-step explanation:

formula:(x-h)^(2)*(y-k)^(2)=r^2

well if you move the circle 3 units left h is (-3), plug it in, you get 3, so it is (x+3)^2*(y-k)^(2)=r^2

if you move the circle 2 units up, plug it in you get (-2), so it is

(x+3)^2*(y-2)^(2)=r^2

now, the radius is 3 (we can see from the graph) so radius ^2 is 9, thus

(x+3)^2*(y-2)^(2)=9

this is the answer, and the option that has it is answer is option 1

1/800 is the right answer

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)