Given that f(x)=x^2+4x-32f(x)=x 2 +4x−32 and g(x)=x-4g(x)=x−4, find (f+g)(x)(f+g)(x) and express the result in standard form.

So your question was not very clear but with (f+g) im guessing thats f(x)+g(x)

So first we add them x^2+4x-32   +   x-4 then we will get x^2 + 5x - 36

Then we need to multiply both

(x^2+5x-36)(x^2+5x-36)

=

(x^2+5x-36)^2

The only reason im not solving it out is because it yields large numbers and you might not understand.

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18