How many zeroes are at the end of 10! = 1∙2 ∙ … ∙ 9∙10?

2.

Step-by-step explanation:

To find the number of trailing zeroes, given n!, we take n and divide it by increasing powers of 5. For example, the number of trailing zeroes in 50! = 50/5 = 10, 50/25 = 2, 10 + 2 = 12 trailing zeroes.

In this case, 10/5 = 2, and since we cannot get an integer from dividing 10 and 25, we are left with this answer.

I hope this helps!

57.09 minus 7.0435 equals

step-by-step explanation:

just subtrach them both and u get the answer of 50.0465

step-by-step explanation:

what was your answer?