100 POINTS + BRAINLIEST Seth is using the figure shown below to prove the Pythagorean Theorem using triangle similarity: In the given triangle DEF, angle D is 90° and segment DG is perpendicular to segment
Part A: Identify a pair of similar triangles. (2 points)
Part B: Explain how you know the triangles from Part A are similar. (4 points)
Part C: If EG = 2 and EF = 8, find the length of segment ED. Show your work. (4 points)

Part A:

Triangles DEG and DGF are similar

Part B:

There's a theorem using a Right Triangle that state: if the altitude is drawn to the hypotenuse of a right triangle (we have segment DG), then the two triangles formed (Triangle DEG and DGF) are similar to que original triangle (Triangle DEF) and to each other.

Hence, triangles DEG and DGF are similar.

Part C:

If EG = 2 and EF = 8, find the length of segment ED

EF is opposite to 90º

ED is adjacent to 90º

We can't calculate using tan once tan 90º is undefined.

Using proportion of similar triangles we have

It is because

6x = 48

i hope this . 6 cards each and a total of $48. dvide each side by 6 and you will have your answer.