Anyone know the answer ASAP please

see explanation

Step-by-step explanation:

Given

4x² + 21x + 27 = 0

Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 4 × 27 = 108 and sum = 21

The factors are 12 and 9

Use the factors to split the x- term

4x² + 12x + 9x + 27 = 0 ( factor the first/second and third/fourth terms )

4x(x + 3) + 9(x + 3) = 0 ← factor out (x + 3) from each term

(x + 3)(4x + 9) = 0

Equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

4x + 9 = 0 ⇒ 4x = - 9 ⇒ x = - 2.25

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Following the same method as the previous question

Given

6x² + 43x - 40 = 0

Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term

product = 6 × - 40 = - 240 and sum = + 43

The factors are + 48 and - 5, thus

6x² + 48x - 5x - 40 = 0

6x(x + 8) - 5(x + 8) = 0

(x + 8)(6x - 5) = 0

x + 8 = 0 ⇒ x = - 8

6x - 5 = 0 ⇒ 6x = 5 ⇒ x =