Use the graphs to estimate both solutions to x^2+x-4=0

No graph so we'll use the quadratic formula

x^2+x-4=0

a = 1

b = 1

c = -4

x = -1 +- sqr root (1^2 - 4 * 1 * -4) / 2

x = (-1 +- sqr root (1 +16) ) / 2

x1 = (-1 + sqr root (17)) / 2

x2 = (-1 - sqr root (17)) / 2

Step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

1,8,15,22,29,36,43,50

step-by-step explanation: