The area of a circle is 18 pi square inches. If the area of a sector of this circle is 6 pi square inches, then which of the following must be the sector's central angle?

Step-by-step explanation:

Area of a sector =

theta is the sector's central angle

Area of the sector =

Given area of a circle = 18πin² and area of a sector = 6πin²

On substituting;

6π =

Dividing both sides by 18π we have;

1/3 =

The sector's central angle is 120°

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b