HELP ASAP I WILL GIVE U BRAINLIEST

The final answer is .

Step-by-step explanation:

Solve the following equation:

-Simplify :

-Simplify :

-Multiply both and :

-Simplify :

-Multiply both and together:

-Simplify :

-Then, on the denominator,  simplify :

Simplify :

Multiply both and together:

Divide and by multiplying by the reciprocal of :

-And you multiply and together:

So, the final answer would be .

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this