10=0.0048(×_50)^2+6The cable is 10 feet above the roadway at horizontal distances of about 4ft and 96 ft. 13ft and 87ft. 21ft and 79 ft. 48ft and 52 ft from the left support

Plz me i need i will give a brain

Suppose that an airline uses a seat width of 16.516.5 in. assume men have hip breadths that are normally distributed with a mean of 14.414.4 in. and a standard deviation of 0.90.9 in. complete parts (a) through (c) below. (a) find the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.516.5 in. the probability is nothing. (round to four decimal places as needed.)

Can someone check if i did this correct. it’s number 4 if you’re wondering.