If two opposite sides of a square are increased by 12 meters and the other sides are decreased by 7 meters, the area of the rectangle that is formed is 66 square meters. Find the area of the original square.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation: