Determine the standard form of the equation of the line that passes through (6, - 9) and (-8, 6). 15x + 14y = - 36
15x + 14y = 36
b.
14x + 15y = -36
15x 14y = - 36
a
C.
d
Please select the best answer from the choices provided
OA
OB
OC
OD

15x + 14y + 36 = 0

Step-by-step explanation:

As we travel from the point (-8, 6) to the point (6, - 9), the increase in x (the "run") is 14 and that in y (the "rise") is -15.  Thus, the slope of the line segment connecting these two points is m = rise / run = -15 / 14.

Let's use the point (6, -9) and the slope m = -15/14 to write the equation of this line:

Adapting y = mx + b, we get:  

-9 = (-15/14)(6) + b, or

-9  = -45/7 + b, which yields b = 45/7 - 9, or  b = 45/7 - 63/7, or b = -18/7

Then the equation is y = (-15/14)x - 18/7

We must put this into "standard form."  Multiplying all three terms by 14 to clear the fractions out, we get:

14y = -15x - 36, or (in standard form):

15x + 14y + 36 = 0

c. (0.6,-1.4)

step-by-step explanation:

hope this

answer: it is d

step-by-step explanation: