A ramp into a building forms a 6° angle with the ground. If the ramp is 8 feet long, how far away from the building is the entry point of the ramp? Round the solution to the nearest hundredth. 5.33 feet 6.05 feet 7.04 feet 7.96 feet

7.68ft

Step-by-step explanation:

Given

Length of Ramp = 8 ft

Angle with the ground = 6°

Required

Distance between ramp and the building.

To calculate this, first, it should be understood that the ramp forms a triangle with the wall with the following parameters.

Hypothenus = Length of ramp

Adjacent = Distance between ramp and wall

Opposite = Height of wall.

Further...

Hypothenus = 8ft

θ = 6°

Adjacent = ?

The relationship between θ, the adjacent and the hypothenus is the cosine function.

Cos(θ) = Adj/Hyp

Cos(6°) = Adj/8

Adj = 8Cos(6°)

Adj = 8 * 0.960170286650366

Adj = 7.681362293202928

Adj = 7.68 (Approximated)

Recall that Adjacent represents the distance between ramp and the wall.

So, distance = 7.68ft

a = 3.14

b = 18

c = 18/5 or 3.6 or 3 3/5

step-by-step explanation: