Find the area of the isosceles triangle

Area of isosceles triangle:

Area = 1/2 × 10 ×

Area = 1/2 × 10 × 12

Area = 60 cm³

60

Step-by-step explanation:

→Before you use the formula to find the area of the isosceles triangle, you must find the height, and to do this, you can use the Pythagorean Theorem:

→We are given the hypotenuse, "c," as 13, and the leg is 5 (we split the base of 10 in half).

→Subtract 25 from both sides:

→To get "b," by itself, take the square root of both sides:

→Formula for area:

A =

A =

A = 60

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )