The slope-intercept form of the equation of a line that passes through point (-3, 8) is y = -x + 6. What is the point-slope form of the equation for this line?
Oy-3=(x + 8)
y +3=(x-8)
y + 8 = }(x-3)
y-8=-? (x + 3)

D. y - 8 = - (x+3)

Step-by-step explanation:

y = - x + 6

Slope m = - 1.

Point (-3,8).

The point-slope form

y - y1 = m(x - x1)

y - 8 = - (x+3)

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

answer: idk

step-by-step explanation: