On the coordinate plane shown, each grid unit represents 10 feet. Polygon QRST has vertices Q(20, 30), R(−10, 30), S(−10, −20), and T(20, −20), and represents the floor plan of a room. Find the perimeter and area of the room.

The coordinate plane is missing, so i have attached it.

Perimeter of room = 140 ft

Area of room = 1200 sq.ft

Step-by-step explanation:

From the cordinate plane attached, we can see the polygon QRST which represents the floor plan of the roo.

Thus;

The length of the sides of the room are;

ST = RQ = 30

QT = RS = 40

Perimeter of a rectangle is the sum of all sides of the rectangle.

Thus, perimeter of the room = (30 × 2) + (40 × 2) = 140 ft

Now, area of a rectangle is the product of two perpendicular sides.

Thus area of room = 40 x 30 = 1200 sq.ft

need points to ask question

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!