Mathematics, 06.06.2020 06:59 genyjoannerubiera
Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(3,−2), B(6, -2), C(6, 5) D(3,5). What is the area of this rectangle
Answers: 1
![AB=\sqrt{(6-3)^{2}+(-2-[-2])^{2}}\\\\ =\sqrt{3^{2}+(-2+2)^{2}}\\\\=\sqrt{9+0}=\sqrt{9}\\\\](/tpl/images/0678/4650/d3810.png)
![BC=\sqrt{(6-6)^{2}+(5-[-2])^{2}} \\\\=\sqrt{0+(5+2)^{2}}\\\\=\sqrt{(7)^{2}}\\](/tpl/images/0678/4650/1fdf5.png)
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Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle:...
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