Un cilindro y un cono tienes la misma altura. Si el volumen del cilindro es menor que el del cono, ¿cuál de las opciones de tamaños de radios pueden tenere ambos? a) radio cilindro=1cm/ radio cono=2cm b)radio cilindro=2cm/radio cono=2cm c)radio cilindro=3cm/radio cono=2cm d)radio cilindro=4cm/radio cono=5cm

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places

one peck is 9.309 quarts

9.309x 2

actually what is a question i don't understand