find K if the sum of the zeros of the polynomial x square - (K + 6 ) x + 2( 2 k - 1) is half the product

k=7

given a quadratic polynomial

ax^2+bx+c

the sum of the roots is given by -(b/a)

and the product of the roots as (c/a)

hence we get sum of roots as -(-(k+6)/1) and product of roots as (2(2k-1))/1

since the sum is equal to half the Product then we get

k+6=2k-1 and solving for k we get 7

the answer is d

step-by-step explanation: