Circle A is located at (6, 5) and has a radius of 4 units. What is the equation of a line that is tangent to circle A from point C (2, 8)? x = 2
y = −0.75x + 9.5
y = 1.33x + 1.66
x = 8

Step-by-step explanation:

1) Taking the Circle A equation, considering that the Circle A is located at (6,5):

2) Since the Circle is located at (6,5), and the other point is (2,8) let's find the slope of  the perpendicular line that's going to be helpful to find one tangent line.

The line goes from the center to the B, with the slope of  

Then the slope of the red one is its opposite inverse:

3)   Tracing the radius from the center, we hit the circumference at D (2,5)

Prolonging that line that'll hit the x coordinate on point (2,0)

So one of the tangents is given by the equation, not function, x=2

the other

4) Using the information on three, for the slope.

1) c 2143.6 cm

2) c 113.0 m

3) a 33.5 ft

4)   d 2 cm

5) c 20 mm

6) 180 in

7) d 120 ft

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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