Dimensions of a cow farm are 650 feet by 255 feet. If 1 inch represents 40 feet, what re the dimensions of the building on the drawing?

the dimensions in the drawing are 16.25 inches by 6.375 inches

Step-by-step explanation:

The first thing is to use the same unit on the scale, that is, they tell us that the scale is 1:40 but that scale cannot be applied because they are different units of measurement.

The answer is preferable to give it in inches because it is more adapted to the measurements in a drawing, therefore we will pass the scale all in inches, knowing that 1 foot is 12 inches:

40 feet * 12 inches / 1 foot = 480 inches, therefore the scale is 1: 480

Now, if we pass the dimensions that give us inches, we are left with:

650 feet * 12 inches / 1 foot = 7800 inches

255 feet * 12 inches / 1 foot = 3060 inches

Now applying the scale:

7800/480 = 16.25

3060/480 = 6.375

It means that the dimensions in the drawing are 16.25 inches by 6.375 inches

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

50- 250 is correct i did that one too

step-by-step explanation: