Consider the system of inequalities and its graph. y ≤ –0.75x y ≤ 3x – 2 On a coordinate plane, 2 solid straight lines are shown. The first line has a negative slope and goes through (negative 8, 6) and (0, 0). Everything below the line is shaded. The second line has a positive slope and goes through (negative 2, negative 8) and (2, 4). Everything to the right of the line is shaded. The section in quadrant 1 is labeled 3, the section in quadrant 2 is labeled 2, the section in quadrant 3 is labeled 1, and the section in quadrant 4 is labeled 4. In which section of the graph does the actual solution to the system lie? 1 2 3 4

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.

the first option is the answer.

what is the model?

step-by-step explanation: