The rectangle has a length of 4x+3 and a width of 3x. Show your work. A. Find the perimeter.

B. Find the area.

C. Find the perimeter and area if x = 8.

  A.  P = 14x+6

  B.  A = 12x^2 +9x

  C.  P = 118; A = 840

Step-by-step explanation:

A. The perimeter is twice the sum of length and width:

  P = 2(L +W) = 2((4x+3) +(3x)) = 2(7x +3)

  P = 14x +6 . . . . the perimeter of the rectangle

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B. The area is the product of length and width:

  A = LW = (4x +3)(3x)

  A = 12x^2 +9x . . . . . the area of the rectangle

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C. When x = 8, these values are ...

  P = 14·8 +6 = 118 . . . . . perimeter in units

  A = 12·8^2 +9·8 = 768 +72 = 840 . . . . . area in square units

the answer is here: : )

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no solution

step-by-step explanation:

there is not enough information in the problem to solve.