A collection of 36 coins consists of nickels, dimes and quarters. There are three fewer quarters than nickels and six more dimes than quarters. How many of each kind of coin is there?

12 nickels, 9 quarters, 15 dimes

Step-by-step explanation:

Let's call the number of nickels n, the number of dimes d, and the number of quarters q. Now, we can set up the following equations:

n+d+q=36

q=n-3

d=q+6

Now, we can do some substitution:

d=(n-3)+6=n+3

Plugging this into the first equation, you get:

n+(n+3)+(n-3)=36

3n=36

n=12

There are twelve nickels, meaning that there are 9 quarters and 15 dimes. Hope this helps!

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.

step-by-step explanation:

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