Two cars are travelling from Toronto to Quebec. Car A left Toronto at 8 a. m. and is moving with an average speed of 70 km/h. Car B left Toronto at 10 a. m. and its average speed is 90 km/h. How many hours will it take for car B to catch car A? (please show all your work Let, So, Equation and Solution and Therefore Statement)

It'll take 7 hours for the car B to cath up to A

Step-by-step explanation:

In order to solve this problem we can write the equation from the distance of each car. Assuming that t = 0 happens when the second car leaves Toronto. When the second car leaves Toronto, the first one is on the road for two hours already, thefeore it travelled a total of:

distance = speed*time = 70*2 = 140

We have:

Car A:

x(t) = 70*t + 140

Car B:

x(t) = 90*t

We now need to find the value of "t" that makes x(t) the same for both cars:

90*t = 70*t + 140

20*t = 140

t = 140 / 20 = 7 h

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation:

cosine

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