PLZ HELP! Robert sketches two rectangular prisms, A and B. Prism A's side lengths are 5 centimeters, 6 centimeters, and 7 centimeters. Prism B's side lengths were twice those of prism A's: 10 centimeters, 12 centimeters, and 14 centimeters. Robert says the surface area of prism B is twice the surface area of prism A. Is he correct? If he is not, how many times as great as prism A's surface area is prism B's surface area?

Robert is 1.___; the Surface area of A is square centimeters. The Surface area of B is square centimeters. B's surface area is times as great as A's.

4 times greater

Step-by-step explanation:

Prism A

SA = 2 (lw+wh+lh)  where l is length w is width and h is height

SA = 2 ( 5*6+ 6*7+ 5*7)

SA = 2(30+42+35)

SA = 2(107)

SA =214

Prism B

SA = 2 (lw+wh+lh)  where l is length w is width and h is height

SA = 2 ( 10*12+ 12*14+ 10*14)

SA = 2(120+168+140)

SA = 2(428)

SA =856

Robert is not correct

856/214 =4

Prism B is 4 times greater

Prism B's surface area is 4 times Prism A's.

The surface area of Prism A is 214 square centimeters.

The surface area of Prism B is 856 square centimeters.

Step-by-step explanation:

To find the surface area of a rectangular prism, use this formula:

Where w is the width, h is the height, and l is the length.

Substitute the values given for Prism A and Prism B into the formula to find each prism's surface area:

Prism A:

Prism B:

Prism B's surface area is 4 times Prism A's.

The surface area of Prism A is 214 square centimeters.

The surface area of Prism B is 856 square centimeters.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204