Please help! You pick a card at random. Without putting the first card back, you pick a second card at random.

What is the probability of picking an even number and then picking an even number?

Simplify your answer and write it as a fraction or whole number.

Probability of picking an even and then even number =

Step-by-step explanation:

Probability of picking a card with even number,

P(even 1) = =

               =

               =

Followed by picking a card which is even without putting the first card back.

So an even card is to be picked out of remaining 3 cards.

P(even 2) =

                =

Now probability of both events = P(even 1) × P(even 2)

=

=

Therefore, probability of both the events will be .

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

step-by-step explanation: