How would you solve dy/dx = 4x - 2, y(-1) = 1 using differential equations?

y=2(x square)-2x-3

Step-by-step explanation:

Let dy with y varibles in a hand

And dx with x variables on the other hand

dy=(4x-2)dx

Then by integration

y=2(square x)-2x+constant

Then substitute by x=-1 and y=1 to find the value of the constant

1=2(1)-2(-1)+ constant

Then constant=-3

Then the equation is

y=2(x square)-2x-3

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204