Please help! You pick a card at random. Without putting the first card back, you pick a second card at random.

What is the probability of picking a 3 and then picking a 3?

Simplify your answer and write it as a fraction or whole number.

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363

the first one

step-by-step explanation:

just id the test.