Since JKLM is a rhombus, JM ≅ LM and JK ≅ LK. MK ≅ MK by the Reflexive Property of Congruence. So, △MJK ≅ △MLK by the Triangle Congruence Theorem. Therefore, ∠JMK ≅ ∠ and ∠JKM ≅ ∠ by CPCTC, so MK bisects ∠JML and ∠JKL. A similar argument shows that JL bisects ∠MJK and ∠MLK. Prove that if a parallelogram is a rhombus, then each diagonal bisects a pair of opposite angles. Complete the proof.

Given: JKLM is a rhombus.

Prove: MK bisects ∠JML and ∠JKL; JL bisects ∠MJK and ∠MLK

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