Use the drawing tool(s) to form the correct answers on the provided graph.
Consider the given function.
h( x ) = ( x + 1 )^2 - 4
Plot the x-intercept(s), y-intercept, vertex, and axis of symmetry of the function.
Will be giving 30 pts, Brainliest, and thanks to anyone who answers plz help quick

Step-by-step explanation:

Recognize from examining this function h( x ) = ( x + 1 )^2 - 4 that it is a quadratic function whose graph is a parabola that opens up.  The vertex is at (h, k):  (-1, -4).  The axis of symmetry is the vertical line passing through the vertex:  x = -1.

To find the y-intercept, let x = 0 and solve for y:  h(0) = (0 + 1)^2 - 4 = -3.  Thus, the y-intercept is (-3, 0).

To find the x-intercepts, set y = 0 and solve for x:  0 = h(x) = (x + 1)^2 - 4, or

(x + 1)^2 = 4.  Taking the square root of both sides, we get x + 1 = ±2, whose roots are x = 1 and x = -3:  (1, 0) and (-3, 0).

Graph all of these points and the axis of symmetry.  Sketch the parabola that goes through these points.