Stefani slices a right rectangular pyramid with a plane and the cross-section is in the
shape of a trapezoid. How does Stefani slice the pyramid?
А
parallel to the base through the vertex
В
perpendicular to the base through the vertex
C parallel to the base but not through the vertex
D perpendicular to the base but not through the vertex

Option D.

Step-by-step explanation:

If Stefani slices the pyramid

Option A). parallel to the base through vertex, cross section will not be a trapezoid.

Option B). perpendicular to the base through the vertex, cross section will be a triangle.

Option C). parallel to the base but not through the vertex, cross section will be a rectangle.

Option D). Perpendicular to the base but not through the vertex, cross section will be a trapezoid.  

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2